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Set 9 Problem number 6


Problem

An object of mass 9 kilograms, suspended by a spring, is released from rest at a point 3.5 meters below its equilibrium position.   The spring has force constant `forceConstant Newtons/meter. 

What is the average of the net forces on the object at the equilibrium point and at the point of release?

Compare the KE of the object near its equilibrium position with the work done on it between release and equilibrium.

Solution

From the given information, we find that the angular velocity is

At t = -.001 second, the angular position is

resulting in a y position of

A similar calculation for t = .001 second yields y position

Thus the y position changes by

in .002 seconds, for an average velocity of

The object, having mass 9 kilograms, will therefore have a kinetic energy of

The force exerted by the spring at the y = 3.5 meter position is

Since the force changes linearly as the object returns to equilibrium, its average between 3.5 meters and equilibrium is

The object moves a distance of 3.5 meters with an average force of 5845 Newtons exerted on it in the direction of motion.  The work done on it is therefore

This is very close to the kinetic energy attained by the object.

Generalized Solution

The average velocity near the equilibrium point, as seen in previous exercises, is near vAve = `sqrt(k/m) * A = `omega^2 * A. The KE near the equilibrium point is therefore near

approx KE near equilibrium = .5 m v^2 = .5 m * (`sqrt(k/m) * A) ^ 2 = .5 k A^2.

The maximum net restoring force experienced is at the maximum displacement A from equilibrium, and is

Fmax = k A.

The net force at the equilibrium point is zero, so the average force between equilibrium and extreme has magnitude

|Fave| = (kA + 0) / 2 = .5 k A.

The distance through which the force acts, between equilibrium and extreme, is A, so the work done has magnitude

| W | = | Fave | * A = .5 k A * A = .5 k A^2.

It is important to note that the expressions for KE and magnitude of work done are identical. 

Explanation in terms of Figure(s), Extension

The figure below depicts an object in SHM at its equilibrium and extreme positions. The KE of the object and the net force on it are indicated at each point. When the work done on the object from extreme to equilibrium is calculated from average force and distance, the result is the same as the KE obtained from the mass and velocity of the object at equilibrium. This is as expected. The work done between extreme and equilibrium is the source of the KE at equilibrium.

Figure(s)

work_and_max_KE_in_SHM.gif (5332 bytes)

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